Integrand size = 15, antiderivative size = 63 \[ \int \frac {1}{x^{5/2} (a+b x)^{3/2}} \, dx=\frac {2}{a x^{3/2} \sqrt {a+b x}}-\frac {8 \sqrt {a+b x}}{3 a^2 x^{3/2}}+\frac {16 b \sqrt {a+b x}}{3 a^3 \sqrt {x}} \]
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Time = 0.01 (sec) , antiderivative size = 63, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.133, Rules used = {47, 37} \[ \int \frac {1}{x^{5/2} (a+b x)^{3/2}} \, dx=\frac {16 b \sqrt {a+b x}}{3 a^3 \sqrt {x}}-\frac {8 \sqrt {a+b x}}{3 a^2 x^{3/2}}+\frac {2}{a x^{3/2} \sqrt {a+b x}} \]
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Rule 37
Rule 47
Rubi steps \begin{align*} \text {integral}& = \frac {2}{a x^{3/2} \sqrt {a+b x}}+\frac {4 \int \frac {1}{x^{5/2} \sqrt {a+b x}} \, dx}{a} \\ & = \frac {2}{a x^{3/2} \sqrt {a+b x}}-\frac {8 \sqrt {a+b x}}{3 a^2 x^{3/2}}-\frac {(8 b) \int \frac {1}{x^{3/2} \sqrt {a+b x}} \, dx}{3 a^2} \\ & = \frac {2}{a x^{3/2} \sqrt {a+b x}}-\frac {8 \sqrt {a+b x}}{3 a^2 x^{3/2}}+\frac {16 b \sqrt {a+b x}}{3 a^3 \sqrt {x}} \\ \end{align*}
Time = 0.08 (sec) , antiderivative size = 38, normalized size of antiderivative = 0.60 \[ \int \frac {1}{x^{5/2} (a+b x)^{3/2}} \, dx=-\frac {2 \left (a^2-4 a b x-8 b^2 x^2\right )}{3 a^3 x^{3/2} \sqrt {a+b x}} \]
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Time = 0.09 (sec) , antiderivative size = 33, normalized size of antiderivative = 0.52
method | result | size |
gosper | \(-\frac {2 \left (-8 b^{2} x^{2}-4 a b x +a^{2}\right )}{3 x^{\frac {3}{2}} \sqrt {b x +a}\, a^{3}}\) | \(33\) |
risch | \(-\frac {2 \sqrt {b x +a}\, \left (-5 b x +a \right )}{3 a^{3} x^{\frac {3}{2}}}+\frac {2 b^{2} \sqrt {x}}{a^{3} \sqrt {b x +a}}\) | \(41\) |
default | \(-\frac {2}{3 a \,x^{\frac {3}{2}} \sqrt {b x +a}}-\frac {4 b \left (-\frac {2}{a \sqrt {x}\, \sqrt {b x +a}}-\frac {4 b \sqrt {x}}{a^{2} \sqrt {b x +a}}\right )}{3 a}\) | \(55\) |
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Time = 0.23 (sec) , antiderivative size = 49, normalized size of antiderivative = 0.78 \[ \int \frac {1}{x^{5/2} (a+b x)^{3/2}} \, dx=\frac {2 \, {\left (8 \, b^{2} x^{2} + 4 \, a b x - a^{2}\right )} \sqrt {b x + a} \sqrt {x}}{3 \, {\left (a^{3} b x^{3} + a^{4} x^{2}\right )}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 219 vs. \(2 (58) = 116\).
Time = 2.73 (sec) , antiderivative size = 219, normalized size of antiderivative = 3.48 \[ \int \frac {1}{x^{5/2} (a+b x)^{3/2}} \, dx=- \frac {2 a^{3} b^{\frac {9}{2}} \sqrt {\frac {a}{b x} + 1}}{3 a^{5} b^{4} x + 6 a^{4} b^{5} x^{2} + 3 a^{3} b^{6} x^{3}} + \frac {6 a^{2} b^{\frac {11}{2}} x \sqrt {\frac {a}{b x} + 1}}{3 a^{5} b^{4} x + 6 a^{4} b^{5} x^{2} + 3 a^{3} b^{6} x^{3}} + \frac {24 a b^{\frac {13}{2}} x^{2} \sqrt {\frac {a}{b x} + 1}}{3 a^{5} b^{4} x + 6 a^{4} b^{5} x^{2} + 3 a^{3} b^{6} x^{3}} + \frac {16 b^{\frac {15}{2}} x^{3} \sqrt {\frac {a}{b x} + 1}}{3 a^{5} b^{4} x + 6 a^{4} b^{5} x^{2} + 3 a^{3} b^{6} x^{3}} \]
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Time = 0.21 (sec) , antiderivative size = 50, normalized size of antiderivative = 0.79 \[ \int \frac {1}{x^{5/2} (a+b x)^{3/2}} \, dx=\frac {2 \, b^{2} \sqrt {x}}{\sqrt {b x + a} a^{3}} + \frac {2 \, {\left (\frac {6 \, \sqrt {b x + a} b}{\sqrt {x}} - \frac {{\left (b x + a\right )}^{\frac {3}{2}}}{x^{\frac {3}{2}}}\right )}}{3 \, a^{3}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 98 vs. \(2 (47) = 94\).
Time = 0.33 (sec) , antiderivative size = 98, normalized size of antiderivative = 1.56 \[ \int \frac {1}{x^{5/2} (a+b x)^{3/2}} \, dx=\frac {2 \, \sqrt {b x + a} {\left (\frac {5 \, {\left (b x + a\right )} b^{2} {\left | b \right |}}{a^{3}} - \frac {6 \, b^{2} {\left | b \right |}}{a^{2}}\right )}}{3 \, {\left ({\left (b x + a\right )} b - a b\right )}^{\frac {3}{2}}} + \frac {4 \, b^{\frac {7}{2}}}{{\left ({\left (\sqrt {b x + a} \sqrt {b} - \sqrt {{\left (b x + a\right )} b - a b}\right )}^{2} + a b\right )} a^{2} {\left | b \right |}} \]
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Time = 0.59 (sec) , antiderivative size = 46, normalized size of antiderivative = 0.73 \[ \int \frac {1}{x^{5/2} (a+b x)^{3/2}} \, dx=\frac {\sqrt {a+b\,x}\,\left (\frac {8\,x}{3\,a^2}-\frac {2}{3\,a\,b}+\frac {16\,b\,x^2}{3\,a^3}\right )}{x^{5/2}+\frac {a\,x^{3/2}}{b}} \]
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